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Quick Maths Trick for Times Tables of 19, 29, 39, 49

High School Student reading a maths blog

Introduction – A Fast Way to Write Times Tables of numbers ending with 9 such as 19, 29, 39, etc

Multiplication Times Tables of numbers ending in 9, such as 19, 29, 39, ..., 99 and so on, follow a remarkably consistent and elegant structure. Instead of memorizing each product separately, you can observe two predictable patterns.

This trick becomes much easier to understand when you are familiar with Arithmetic Progression (AP). In the multiplication tables of numbers ending in 9 (such as 19, 29, 39, ...), the digits to the left of the unit digit follow a clear Arithmetic Progression. The sequence starts with the non-unit digit of the multiplicand and increases by a constant value each time. Recognizing this AP pattern helps you construct the table systematically instead of multiplying each step separately. If you are not familiar with Arithmetic Progression, refer to the brief explanation provided at the end of this article before exploring the pattern in detail.

The Two Patterns Behind the Trick

Let's take the Times Table of 39 as an example.

39✕1=3939✕2=7839✕3=11739✕4=15639✕5=19539✕6=23439✕7=27339✕8=31239✕9=35139✕10=390

The products are: 39, 78, 117, 156, 195, 234, 273, 312, 351, 390

Pattern I: Unit Digits Decrease Sequentially

The unit digit from each product form this sequence: 9, 8, 7, 6, 5, 4, 3, 2, 1, 0. The unit digit of nth product can be found using 10 - n.

Pattern II: The Remaining Digits Form an Arithmetic Progression

The remaining digits from each product: 3, 7, 11, 15, 19, 23, 27, 31, 35, 39. This is an Arithmetic Progression (AP) with the first term (a) = 3 (from 39) and common difference (d) = a + 1 = 4. These remaining digits of a nth product can be found using a + (n - 1)d.

How to Apply the Pattern

These two patterns give us the formulae to determine the products.

From the multiplicands (such as 19, 29, 39, ..., 99 and so on), we get the first term (a). This is simply the non-unit digit of the multiplicand. For example, the first term (a) will be 1 for 19, 2 for 29, 3 for 39 and so on.

Common Difference (d): a + 1
Unit Digit: 10 - n
Remaining Digits: a + (n - 1)d

Where, a is the first term, d is the common difference and n is any one of the multipliers from 1 to 10.

See the Pattern in Action

Writing down the Times Table of 19

a = 1 (from 19) d = a + 1 = 2
19
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
19 1 19
 
1
19
9
19 2 38
1 2
3
38
8
19 3 57
3 2
5
57
7
19 4 76
5 2
7
76
6
19 5 95
7 2
9
95
5
19 6 114
9 2
11
114
4
19 7 133
11 2
13
133
3
19 8 152
13 2
15
152
2
19 9 171
15 2
17
171
1
19 10 190
17 2
19
190
0

Writing down the Times Table of 29

a = 2 (from 29) d = a + 1 = 3
29
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
29 1 29
 
2
29
9
29 2 58
2 3
5
58
8
29 3 87
5 3
8
87
7
29 4 116
8 3
11
116
6
29 5 145
11 3
14
145
5
29 6 174
14 3
17
174
4
29 7 203
17 3
20
203
3
29 8 232
20 3
23
232
2
29 9 261
23 3
26
261
1
29 10 290
26 3
29
290
0

Writing down the Times Table of 39

a = 3 (from 39) d = a + 1 = 4
39
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
39 1 39
 
3
39
9
39 2 78
3 4
7
78
8
39 3 117
7 4
11
117
7
39 4 156
11 4
15
156
6
39 5 195
15 4
19
195
5
39 6 234
19 4
23
234
4
39 7 273
23 4
27
273
3
39 8 312
27 4
31
312
2
39 9 351
31 4
35
351
1
39 10 390
35 4
39
390
0

Writing down the Times Table of 49

a = 4 (from 49) d = a + 1 = 5
49
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
49 1 49
 
4
49
9
49 2 98
4 5
9
98
8
49 3 147
9 5
14
147
7
49 4 196
14 5
19
196
6
49 5 245
19 5
24
245
5
49 6 294
24 5
29
294
4
49 7 343
29 5
34
343
3
49 8 392
34 5
39
392
2
49 9 441
39 5
44
441
1
49 10 490
44 5
49
490
0

Writing down the Times Table of 59

a = 5 (from 59) d = a + 1 = 6
59
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
59 1 59
 
5
59
9
59 2 118
5 6
11
118
8
59 3 177
11 6
17
177
7
59 4 236
17 6
23
236
6
59 5 295
23 6
29
295
5
59 6 354
29 6
35
354
4
59 7 413
35 6
41
413
3
59 8 472
41 6
47
472
2
59 9 531
47 6
53
531
1
59 10 590
53 6
59
590
0

Writing down the Times Table of 69

a = 6 (from 69) d = a + 1 = 7
69
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
69 1 69
 
6
69
9
69 2 138
6 7
13
138
8
69 3 207
13 7
20
207
7
69 4 276
20 7
27
276
6
69 5 345
27 7
34
345
5
69 6 414
34 7
41
414
4
69 7 483
41 7
48
483
3
69 8 552
48 7
55
552
2
69 9 621
55 7
62
621
1
69 10 690
62 7
69
690
0

Writing down the Times Table of 79

a = 7 (from 79) d = a + 1 = 8
79
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
79 1 79
 
7
79
9
79 2 158
7 8
15
158
8
79 3 237
15 8
23
237
7
79 4 316
23 8
31
316
6
79 5 395
31 8
39
395
5
79 6 474
39 8
47
474
4
79 7 553
47 8
55
553
3
79 8 632
55 8
63
632
2
79 9 711
63 8
71
711
1
79 10 790
71 8
79
790
0

Writing down the Times Table of 89

a = 8 (from 89) d = a + 1 = 9
89
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
89 1 89
 
8
89
9
89 2 178
8 9
17
178
8
89 3 267
17 9
26
267
7
89 4 356
26 9
35
356
6
89 5 445
35 9
44
445
5
89 6 534
44 9
53
534
4
89 7 623
53 9
62
623
3
89 8 712
62 9
71
712
2
89 9 801
71 9
80
801
1
89 10 890
80 9
89
890
0

Writing down the Times Table of 99

a = 9 (from 99) d = a + 1 = 10
99
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
99 1 99
 
9
99
9
99 2 198
9 10
19
198
8
99 3 297
19 10
29
297
7
99 4 396
29 10
39
396
6
99 5 495
39 10
49
495
5
99 6 594
49 10
59
594
4
99 7 693
59 10
69
693
3
99 8 792
69 10
79
792
2
99 9 891
79 10
89
891
1
99 10 990
89 10
99
990
0

What is Arithmetic Progression (AP)?

Arithmetic Progression (AP) is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant value is called the common difference (d). If the first term is a, then the sequence is formed by repeatedly adding d to each term:

a, a + d, a + 2d, a + 3d, ...

The nth term of an Arithmetic Progression is given by the formula:

Tₙ = a + (n − 1)d

This Pattern Works for All Numbers Ending in 9

This trick is not limited to numbers from 19 to 99. In fact, the same pattern appears in the multiplication tables of any number that ends with 9 including the single-digit number 9. The unit digits of the products still decrease from 9 to 0, and the remaining digits continue to follow a clear arithmetic progression.

Let's take the Times Table of 479 as an example.

Writing down the Times Table of 479

a = 47 (from 479) d = a + 1 = 48
479
The Pattern
Remaining Digits in AP
(Pattern II)
a + (n - 1)d
Product
Unit Digit
(Pattern I)
10 - n
479 1 479
 
47
479
9
479 2 958
47 48
95
958
8
479 3 1437
95 48
143
1437
7
479 4 1916
143 48
191
1916
6
479 5 2395
191 48
239
2395
5
479 6 2874
239 48
287
2874
4
479 7 3353
287 48
335
3353
3
479 8 3832
335 48
383
3832
2
479 9 4311
383 48
431
4311
1
479 10 4790
431 48
479
4790
0

You can explore this pattern yourself on our Multiplication Times Tables: Reference Chart page. Under Custom option, enter multiplicands up to 999 and generate their tables instantly. Try numbers such as 9, 239, 489, 529, 779, or any number ending in 9, and observe how the same two patterns appear consistently in their times tables.